[ a_1 = g \cdot \frac{4m - m_1}{4m + m_1}, \quad a_2 = -a_3 = g \cdot \frac{m_1}{4m + m_1} ]
In Problem 3, what happens if the hoop is also oscillating vertically? (You are now ready for the IPhO.) If you enjoyed this article, download the full PDF containing 50 additional mechanics problems with step-by-step video-linked solutions. [ a_1 = g \cdot \frac{4m - m_1}{4m
( \frac{dU_{eff}}{d\theta} = 0 ) [ mgR \sin\theta - m\omega^2 R^2 \sin\theta \cos\theta = 0 ] [ mR \sin\theta ( g - \omega^2 R \cos\theta ) = 0 ] [ a_1 = g \cdot \frac{4m - m_1}{4m