He applied the (from the First Law of Thermodynamics, ΔU = Q – W, with Q=0 for rapid compression):
Kael derived the energy balance: Total exhaust energy = Energy to turbine + Energy bypassed + Waste heat + Entropy. turbo physics grade 12 pdf
“More air means more fuel can be burned,” Kael said. “That’s the power gain.” But 135°C air caused engine knock. Dr. Vane handed him an intercooler—an air-to-air radiator. After the intercooler, temperature dropped to 45°C while pressure only dropped to 1.7 atm. He applied the (from the First Law of
New density at 1.7 atm, 45°C (318 K): ρ = (1.7×101325)/(287×318) ≈ 172252/91266 ≈ 1.89 kg/m³ New density at 1
For air, γ = 1.4, so (0.4/1.4) = 0.286.
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T₂ = 298 K × (1.8/1.0)^0.286 T₂ = 298 × 1.8^0.286 1.8^0.286 ≈ 1.178 T₂ ≈ 351 K → 78°C (theoretical ideal).